Centrifugal Force Calculator

| Added in Physics

What Is Centrifugal Force?

Whirl a bucket of water over your head fast enough and the water stays in the bucket — even at the top, upside down. The outward push that seems to slam everything toward the outside of a curve is what we call centrifugal force.

Strictly speaking, physicists classify it as a fictitious force: nothing is actually pushing outward. What is really happening is inertia — every object wants to travel in a straight line, so when something forces it around a bend (a string, a road surface, a spinning drum), the object pushes back against whatever is turning it. That resistance shows up as an apparent outward force in the rotating frame of reference, and it is very measurable. Engineers rely on it to size centrifuges, design banked curves, test astronaut tolerances and build amusement rides.

The Centrifugal Force Formula

Using the object's linear speed $v$ along the circle:

[
F = \frac{mv^{2}}{r}
]

Where:

  • F is the centrifugal force in newtons (N)
  • m is the mass of the object in kilograms (kg)
  • v is the speed along the circular path in metres per second (m/s)
  • r is the radius of the path in metres (m)

If you know the angular speed $\omega$ (in radians per second) instead, use the equivalent form:

[
F = m\omega^{2}r
]

Both formulas are the same statement, because $v = \omega r$: substitute once and $m(\omega r)^2 / r$ collapses to $m\omega^2 r$. Notice that velocity enters squared — double the speed and the force quadruples.

Worked Example: A Ball on a String

A 5 kg ball swings in a circle of radius 2 m at 10 m/s:

[
F = \frac{mv^{2}}{r} = \frac{5 \times 10^{2}}{2} = \frac{500}{2} = 250 \text{ N}
]

Now confirm it with the angular-speed form. The angular speed is $\omega = v/r = 10/2 = 5$ rad/s:

[
F = m\omega^{2}r = 5 \times 5^{2} \times 2 = 5 \times 25 \times 2 = 250 \text{ N}
]

Both routes agree: 250 N, about 5.1 g on the ball — the same pull a fighter pilot feels in a hard manoeuvre. Try entering these numbers above; the calculator reproduces them exactly.

Centrifugal vs Centripetal: Two Sides of One Turn

Students mix these up constantly, so here is the clean split:

Centripetal force Centrifugal force
Direction Toward the centre Apparent push outward
Real or fictitious Real (tension, friction, gravity…) Fictitious (inertia viewed from the rotating frame)
Formula Same magnitude: $mv^2/r$, directed inward Same magnitude: $mv^2/r$, directed outward
Example Friction gripping a car's tyres through a bend The sideways slide you feel across the seat

They are always equal in size and opposite in direction. The inward force is the cause; the outward feeling is the effect you experience from inside the turn.

Where the Squared Velocity Bites

Because $v$ is squared, small speed changes create huge force changes:

Speed on a 50 m bend (same car) Relative force
50 km/h 1×
70 km/h ≈ 2×
100 km/h 4×

This is exactly why speed limits drop sharply before tight curves: the grip available from the tyres is fixed, but the demanded force grows with the square of your speed. The same logic sets spin speeds in washing machines and laboratory centrifuges — a modest radius spun very fast generates enormous separating forces.

Quick Recap

  • Centrifugal force is the apparent outward push in a rotating frame, caused by inertia.
  • Formula: $F = mv^2/r$, or equivalently $F = m\omega^2 r$ with $v = \omega r$.
  • Velocity enters squared: twice the speed means four times the force.
  • Centripetal pulls inward (real); centrifugal seems to push outward (fictitious) — equal in magnitude.
  • Use the calculator above to check any mass–speed–radius combination and see the g-force instantly.

Once you have the force on a rotating body, the RPM to G-Force Calculator is a natural next step for exploring spin-driven loads.

Frequently Asked Questions

Centrifugal force is the apparent outward push you feel when you move in a circle — your body trying to carry on in a straight line while the car, ride or centrifuge turns underneath you. It is measured in newtons (N) and is what presses you into the car door on a sharp turn.

The formula is F = mv²/r: multiply the mass in kilograms by the square of the velocity in metres per second, then divide by the radius in metres. Written with angular speed instead, it becomes F = mω²r, because v = ωr — both forms give exactly the same answer.

Physicists call it a fictitious or pseudo-force: nothing is actually pushing you outward. What really acts is the centripetal force pulling you inward, and the outward sensation is your own inertia resisting that turn. In the rotating reference frame, though, centrifugal force behaves exactly like a real force, which is why engineers use it constantly.

Use the link v = ωr, where ω is the angular speed in radians per second. Substituting gives F = m(ωr)²/r = mω²r²/r = mω²r. So a 5 kg mass at ω = 5 rad/s on a 2 m radius feels F = 5 × 25 × 2 = 250 N — identical to the linear-velocity calculation.

Because velocity appears squared in F = mv²/r. At double the speed the numerator mv² is four times larger, so the force is four times larger for the same mass and radius. This is why cornering at 100 km/h puts four times the load on a tyre than cornering at 50 km/h on the same bend.

The result comes out in newtons (N), the SI unit of force, after the calculator converts your inputs to kilograms, metres per second and metres. As a sense check, 1 N is roughly the weight of a small apple, and dividing the force by the object weight tells you the g-force it experiences.

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